Mars does not have a magnetosphere. Any discussion of humans ever settling the red planet can stop right there, but of course it never does. Do you have a low-cost plan for, uh, creating a gigantic active dynamo at Mars’s dead core? No? Well. It’s fine. I’m sure you have some other workable, sustainable plan […]

By Albert Burneko

9:00 AM EDT on September 11, 2024

Mars does not have a magnetosphere. Any discussion of humans ever settling the red planet can stop right there, but of course it never does. Do you have a low-cost plan for, uh, creating a gigantic active dynamo at Mars’s dead core? No? Well. It’s fine. I’m sure you have some other workable, sustainable plan for shielding live Mars inhabitants from deadly solar and cosmic radiation, forever. No? Huh. Well then let’s discuss something else equally realistic, like your plan to build a condo complex in Middle Earth.

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  • bloodfart@lemmy.ml
    1·
    2 months ago

    How much (metal, refined, produced on earth) wire would you say is required to produce an air (actually vacuum, but we know air core really well so there’s math for them) core electromagnet which can generate a field capable of deflecting solar wind over the area of its pv array? In order to maintain that field strength, how much current is required? Can it be supplied by a pv array equal in area to the effective field area? How many of those are needed to cover the area of mars?

    That’s-a lotta metal!

    Also speaking as a person who deals with e-waste daily, it’s both by volume and mass composed of petroleum products. Fiberglass is reenforced plastic. Ics are 90% plastic by volume. Discrete components are made of petroleum distillates in a lot of cases and encased in them in even more cases!

    Even if you only considered the boards as the e-waste and not the plastic cases and bodies themselves, those dont exist in a vacuum like our hypothetical electromagnets, a reduction in printer boards means fewer printers which are almost completely just plastic.