There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices.
Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.
If C is the correct choice, then that is only one answer out of four that is correct, meaning you only had a 25% chance to answer correctly. You’ve created a logical paradox.
25% occurs twice, so in reality there are only 3 outcomes from your pick. Since you know 25% is incorrect from this, that is 30% of the total answers, but also 50% of total options. Via this, you can conclude that both b and c are valid answers, depending on whether you view it in relation to outcomes or in relation to options. If you view the 3 outcomes, then you have a 60% chance of being right, but if you view the 4 options, you have a 50% chance of being right. Both 50% and 60% being accepted as anwswers solves the paradoxical nature of the question.
If I’m choosing at random between 50% and 25%, then I have 50% chance to get 50%. It is random, but I eliminate the weird options.
I do that sometimes.
Even at random, 25% chance are the only options that are wrong, and they account for 50% of the choices and 30% of the true options. Otherwise, the question has no correct answer due to the two 25%s.
One caviat of course is that in reality, 2/3 is 66.6% and not 60%, but ya kno.
There is absolutely no way it is 60%. Because you can never have 60% chances of picking anything particular when there are only 4 choices. Knowing this, the answer is either 25% or 50%. Two effective choices, so the answer is C, 50%.
If C is the correct choice, then that is only one answer out of four that is correct, meaning you only had a 25% chance to answer correctly. You’ve created a logical paradox.
25% occurs twice, so in reality there are only 3 outcomes from your pick. Since you know 25% is incorrect from this, that is 30% of the total answers, but also 50% of total options. Via this, you can conclude that both b and c are valid answers, depending on whether you view it in relation to outcomes or in relation to options. If you view the 3 outcomes, then you have a 60% chance of being right, but if you view the 4 options, you have a 50% chance of being right. Both 50% and 60% being accepted as anwswers solves the paradoxical nature of the question.
If I’m choosing at random between 50% and 25%, then I have 50% chance to get 50%. It is random, but I eliminate the weird options.
I do that sometimes.
the key word here is at random, you imagine a situation where you’re doing it at random, but you’re not actually answering randomly are you?
Even at random, 25% chance are the only options that are wrong, and they account for 50% of the choices and 30% of the true options. Otherwise, the question has no correct answer due to the two 25%s.
One caviat of course is that in reality, 2/3 is 66.6% and not 60%, but ya kno.