The sun is also happy :)

If you read the digits in reverse it matches ISO 8601.

And yes I know it’s a joke (:

MAYOR!

Did someone say Cat Soup?

Now I want to know the kitty’s name, is it sword-related?

https://lemmy.sdf.org/post/1168677

Nim

import ../aoc, strutils, sequtils, tables

type
  Rules = ref Table[int, seq[int]]

#check if an update sequence is valid
proc valid(update:seq[int], rules:Rules):bool =
  for pi, p in update:
    for r in rules.getOrDefault(p):
      let ri = update.find(r)
      if ri != -1 and ri < pi:
        return false
  return true

proc backtrack(p:int, index:int, update:seq[int], rules: Rules, sorted: var seq[int]):bool =
  if index == 0:
    sorted[index] = p
    return true
  
  for r in rules.getOrDefault(p):
    if r in update and r.backtrack(index-1, update, rules, sorted):
      sorted[index] = p
      return true
  
  return false

#fix an invalid sequence
proc fix(update:seq[int], rules: Rules):seq[int] =
  echo "fixing", update
  var sorted = newSeqWith(update.len, 0);
  for p in update:
    if p.backtrack(update.len-1, update, rules, sorted):
      return sorted
  return @[]

proc solve*(input:string): array[2,int] =
  let parts = input.split("\r\n\r\n");
  
  let rulePairs = parts[0].splitLines.mapIt(it.strip.split('|').map(parseInt))
  let updates = parts[1].splitLines.mapIt(it.split(',').map(parseInt))
  
  # fill rules table
  var rules = new Rules
  for rp in rulePairs:
    if rules.hasKey(rp[0]):
      rules[rp[0]].add rp[1];
    else:
      rules[rp[0]] = @[rp[1]]
      
  # fill reverse rules table
  var backRules = new Rules
  for rp in rulePairs:
    if backRules.hasKey(rp[1]):
      backRules[rp[1]].add rp[0];
    else:
      backRules[rp[1]] = @[rp[0]]
  
  for u in updates:
    if u.valid(rules):
      result[0] += u[u.len div 2]
    else:
      let uf = u.fix(backRules)
      result[1] += uf[uf.len div 2]

I thought of doing a sort at first, but dismissed it for some reason, so I came up with this slow and bulky recursive backtracking thing which traverses the rules as a graph until it reaches a depth equal to the given sequence. Not my finest work, but it does solve the puzzle :)

Nim

import ../aoc, strutils

type
  Cell* = tuple[x,y:int]

#the 8 grid direction
const directions : array[8, Cell] = [
  (1, 0), (-1, 0),
  (0, 1), ( 0,-1),
  (1, 1), (-1,-1),
  (1,-1), (-1, 1)
]

const xmas = "XMAS"

#part 1
proc searchXMAS*(grid:seq[string], x,y:int):int =
  #search in all 8 directions (provided we can find a full match in that direction)
  let w = grid[0].len
  let h = grid.len
  
  for dir in directions:
    # check if XMAS can even fit
    let xEnd = x + dir.x * 3
    let yEnd = y + dir.y * 3
    if xEnd < 0 or xEnd >= w or
       yEnd < 0 or yEnd >= h:
      continue;
    
    #step along direction
    var matches = 0
    for s in 0..3:
      if grid[y + dir.y * s][x + dir.x * s] == xmas[s]:
        inc matches
        
    if matches == xmas.len:
      inc result

#part 2
proc isMAS(grid:seq[string], c, o:Cell):bool=
  let ca : Cell = (c.x+o.x, c.y+o.y)
  let cb : Cell = (c.x-o.x, c.y-o.y)
  let a = grid[ca.y][ca.x]
  let b = grid[cb.y][cb.x]
  (a == 'M' and b == 'S') or (a == 'S' and b == 'M')

proc searchCrossMAS*(grid:seq[string], x,y:int):bool =
  grid[y][x] == 'A' and
  grid.isMAS((x,y), (1,1)) and
  grid.isMAS((x,y), (1,-1))

proc solve*(input:string): array[2,int] =
  let grid = input.splitLines
  let w = grid[0].len
  let h = grid.len
  
  #part 1
  for y in 0..<h:
    for x in 0..<w:
      result[0] += grid.searchXMAS(x, y)
  
  #part 2, skipping borders
  for y in 1..<h-1:
    for x in 1..<w-1:
      result[1] += (int)grid.searchCrossMAS(x, y)

Part 1 was done really quickly. Part 2 as well, but the result was not accepted…

Turns out +MAS isn’t actually a thing :P

Nim

import ../aoc, re, sequtils, strutils, math

proc mulsum*(line:string):int=
  let matches = line.findAll(re"mul\([0-9]{1,3},[0-9]{1,3}\)")
  let pairs = matches.mapIt(it[4..^2].split(',').map(parseInt))
  pairs.mapIt(it[0]*it[1]).sum

proc filter*(line:string):int=
  var state = true;
  var i=0
  while i < line.len:
    if state:
      let off = line.find("don't()", i)
      if off == -1:
        break
      result += line[i..<off].mulsum
      i = off+6
      state = false
    else:
      let on = line.find("do()", i)
      if on == -1:
        break
      i = on+4
      state = true
      
  if state:
    result += line[i..^1].mulsum

proc solve*(input:string): array[2,int] =
  #part 1&2
  result = [input.mulsum, input.filter]

I had a nicer solution in mind for part 2, but for some reason nre didn’t want to work for me, and re couldn’t give me the start/end or all results, so I ended up doing this skip/toggle approach.

Also initially I was doing it line by line out of habit from other puzzles, but then ofc the don't()s didn’t propagate to the next line.

Could be Neon Genesis Evangelion, there’s a scene where Shinji and Asuka are in the pod together, though they are both human.

Nim

import strutils, times, sequtils, sugar

# check if level transition in record is safe
proc isSafe*(sign:bool, d:int): bool =
  sign == (d>0) and d.abs in 1..3;

#check if record is valid
proc validate*(record:seq[int]): bool =
  let sign = record[0] > record[1];
  return (0..record.len-2).allIt(isSafe(sign, record[it] - record[it+1]))

# check if record is valid as-is
# or if removing any item makes the record valid
proc validate2*(record:seq[int]): bool =
  return record.validate or (0..<record.len).anyIt(record.dup(delete(it)).validate)

proc solve*(input:string): array[2,int] =
  let lines = input.readFile.strip.splitLines;
  let records = lines.mapIt(it.splitWhitespace.map(parseInt));
  result[0] = records.countIt(it.validate);
  result[1] = records.countIt(it.validate2);

I got stuck on part 2 trying to check everything inside a single loop, which kept getting more ugly. So then I switched to just deleting one item at a time and re-checking the record.

Reworked it after first finding the solution to compress the code a bit, though the range iterators don’t really help with readability.

I did learn about the sugar import, which I used to make the sequence duplication more compact: record.dup(delete(it).

Shoko is the only nonstandard plugin I use.

Ok, that’s really awesome!

Thinking of using nim again like last year

They indeed look so alike! She looks comfy :)

🤍 Enjoy times 🤍

AI gets it right in the end :)

That is amazing, glad you are reunited!

The real issue is already going 3 months without source control.

That loop is so satisfying :)

Your package manager of choice :)