

the problem is that due to the algorithmic nature of social media it ends up getting pushed to people who don’t want to see it.
sapphic. hater of capital letters. bunny and cat mum. renn faire enjoyer. theatre kid. squishmallows enthusiast. taylor swift lover era appreciator. marisha ray defender. houseplant addict. multiple social accounts haver. i’m also on lemmy.blahaj.zone :)
the problem is that due to the algorithmic nature of social media it ends up getting pushed to people who don’t want to see it.
spotify has always been shitty tbh; given the choice between spotify and nothing, you’re better off with nothing
good now stop cooperating with us and ice.
writing code via ai is the dumbest thing i’ve ever heard because 99% of the time ai gives you the wrong answer, “corrects it” when you point it out, and then gives you back the first answer when you point out that the correction doesn’t work either and then laughs when it says “oh hahaha we’ve gotten in a loop”
they did convince me to upgrade to linux mint 22 tho
dmca for what they’re not distributing anything spotify can go fuck themselves
every time i try to have a moment of silence for charlie kirk i end to giggling because that stupid fuck is in hell
i’m not a foreigner so i’ll say it. the only good thing charlie kirk did in life was become the world’s largest gender neutral toilet.
marty yer going through the window again
new york is that a’way
looks at libreoffice
pats libreoffice
kinda wish he would come back in the 2300 arena but i know arthur ashe would make more sense being from nyc
subhuman implies a level of humanity and billionaires don’t have that.
a bullet but with cat ears and a choker
question what the fuck is wrong with the midwest
fuck now i want tater tots
media has more in common with a piece of shit nazi than kids going to school.
charlies entire career was made in political violence against minorities
seems like this wasnt even an accurate report
https://bsky.app/profile/thelincoln.bsky.social/post/3lyl5ljm2h22m
bool isOdd(int num) { const oddNumbers = []; for (let i = 1; i <= 10000000; i += 2) { oddNumbers.push(i); } if (offNumbers.includes(num) { return true; } }