Turns out no solution exists.

  • nandeEbisu@lemmy.world
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    4 days ago

    Even though the lines are infinitely far away from the x axis, they are still the same distance apart. Even if you parameterizing the slope of one line and modify it:

    Ax - 2 = x Intersection is Ax - 2 - x = 0 x = 2 / (A - 1)

    So they become parallel as A approaches 1

    So the inter section point for A = 1 is lim 2 / (A-1) as A -> 1

    Which is 2/0, or undefined.

    You can gain a lot of insight with graphical explanations, but sometimes can fall into traps, so it’s helpful to translate that to formal notation sometimes.

    • Gustephan@lemmy.world
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      4 days ago

      So like, in any real system as x approaches infinity the difference between x and x+2 will fall below measurement error and make x = x+2 functionally true (far field small angle approximation and whatnot.) This kind of situation comes up in optics when you’re finding different f points on lenses. I think it’s more a case of “both ways to consider that math are useful in different regimes/circumstances.” If a student in a proof based math class i was teaching came at me with the graphical explanation I’d tell them to try again, but if one of my junior engineers came to my office with concerns about the difference between x and x+2 at x=50000 or something id take it as an opportunity to teach them why it probably doesn’t matter.

      • nandeEbisu@lemmy.world
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        3 days ago

        Oh, in an engineering context, yeah. I think that’s more because you’re looking at the relative difference between the two, or

        ((x-2)-x)/x, which is -2/x, which is 0 as x approaches infinity.

    • iAvicenna@lemmy.world
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      3 days ago

      I can do equations for you:

      y = ax

      y = x+2

      with a>1. Intersection at x=2/(a-1). As a goes to 1, first line approaches y=x and the intersection point goes to infinity.