Day 3: Mull It Over

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FAQ

  • VegOwOtenks@lemmy.world
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    2 days ago

    I couldn’t figure it out in haskell, so I went with bash for the first part

    Shell

    cat example | grep -Eo "mul\([[:digit:]]{1,3},[[:digit:]]{1,3}\)" | cut -d "(" -f 2 | tr -d ")" | tr "," "*" | paste -sd+ | bc
    

    but this wouldn’t rock anymore in the second part, so I had to resort to python for it

    Python

    import sys
    
    f = "\n".join(sys.stdin.readlines())
    
    f = f.replace("don't()", "\ndon't()\n")
    f = f.replace("do()", "\ndo()\n")
    
    import re
    
    enabled = True
    muls = []
    for line in f.split("\n"):
        if line == "don't()":
            enabled = False
        if line == "do()":
            enabled = True
        if enabled:
            for match in re.finditer(r"mul\((\d{1,3}),(\d{1,3})\)", line):
                muls.append(int(match.group(1)) * int(match.group(2)))
            pass
        pass
    
    print(sum(muls))
    
    • Hammerheart@programming.dev
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      3 hours ago

      My first insinct was similar, add line breaks to the do and dont modifiers. But I got toa caught up thinking id have to keep track of the added characters, I wound up just abusing split()-

    • reboot6675@sopuli.xyz
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      2 days ago

      Really cool trick. I did a bunch of regex matching that I’m sure I won’t remember how it works few weeks from now, this is so much readable