I’m stuck on one of these intricacies now! I saw some of the ideas on how other people did it but i honestly have no clue what i did wrong. Got any tricky examples to share?
I just solved it. I printed every set of integers in the format “Result: [theTwoDigits], from string: [inputString]” and mannually checked all of them. Eventually found the edge case that was causing troubles. It was a typo.
Oh god, sorry to hear that 😅i’m feeling desperate enough to try that, i just wrote a different implementation and i get the same (wrong) result. At this point I just want to know what i misunderstood or mistyped cuz its driving me crazy
The bug is some strings can have overlapping characters.
onEight threEight fivEight. There are more cases.
So if you do a search and replace your string becomes 1ight 3ight and the second number does not get found.
Possible fixes:
Search and replace and add the extra letter: oneEigh then search and replace.
Search and replace words to numbers but put some extra letters in just in case.
Thanks, I managed to find the culprit in the end however - I was using a forward-look of 5 characters for finding if it matches a word so in a string of a3two for example, it would register the two before the 3. It was an easy fix once i found the issue.
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I’m stuck on one of these intricacies now! I saw some of the ideas on how other people did it but i honestly have no clue what i did wrong. Got any tricky examples to share?
I just solved it. I printed every set of integers in the format “Result: [theTwoDigits], from string: [inputString]” and mannually checked all of them. Eventually found the edge case that was causing troubles. It was a typo.
Oh god, sorry to hear that 😅i’m feeling desperate enough to try that, i just wrote a different implementation and i get the same (wrong) result. At this point I just want to know what i misunderstood or mistyped cuz its driving me crazy
The bug is some strings can have overlapping characters. onEight threEight fivEight. There are more cases. So if you do a search and replace your string becomes 1ight 3ight and the second number does not get found.
Possible fixes: Search and replace and add the extra letter: oneEigh then search and replace. Search and replace words to numbers but put some extra letters in just in case.
Thanks, I managed to find the culprit in the end however - I was using a forward-look of 5 characters for finding if it matches a word so in a string of a3two for example, it would register the two before the 3. It was an easy fix once i found the issue.